A. Katjuha
ŤJatvizj-2014ť [32]

1.a7-b8 d6xf4 2.a1-b2 c3xa1 3.c7-d8 a5xc7 4.d8xh8 -M:

[ 
LS:  
4.b8xh8 
? 
a1-b2 
/c3/d4 
5.h8xa1 
e3-f2 
= 
] 

[ 4...a1-b2 5.h8xa1 x ... ]

5.b8-e5 a1xf6 6.h8xg1 x 2-0